Talk:Advanced Technology Leisure Application Simulator

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Consistent vandalism over months[edit]

Some strange, Lego obsessed weirdo child has been adding their simulator fanfiction to this page for months.

I’ve reverted it an added a desperately needed cleanup tag. Keep a watch in case they come back. 50.232.76.252 (talk) 02:08, 19 June 2023 (UTC)[reply]

Other[edit]

Has anyone looked into or studied the sinulator technology in general. when it started and what application is used for?

I worked on this simulator for a while...what do you want to know? Simulators date back to the original Link Trainer - they are used for simulating all sorts of vehicles - from jet fighters, to airliners, tanks, cars, you name it. SteveBaker (talk) 22:31, 5 October 2009 (UTC)[reply]

Approximate size of the simulator units[edit]

For anyone who has previously worked on the simulators, what is the approximate size of each unit? (length by width by height approximate, please) — Preceding unsigned comment added by 122.108.90.66 (talk) 12:40, 12 April 2013 (UTC)[reply]

I know from visiting that the Star Tours flight simulators at Disneyland have 40 seats each. The seats are approximately ~18in/45cm wide. There are 5 rows, the front two rows have 8 seats apiece, the third row has 7 seats, the fourth 8 seats as with the first two rows, and the rear row has 9 seats. The elevation increases roughly 3in/8cm per row so those in the back can see over those in the front. The doors on the simulators are about 6.5ft/200cm tall to allow the public to enter and exit. From my recollection, there is about 1ft/35cm of height above the rear door to the top of the simulator, and the elevation change would add another 15in/38cm. Not clear on how far below the floor it extends; it's irregularly shaped. The doors seemed to be about 3in/8cm wide and just about touched both the left and right seats of the last row. So multiplying the seat width by 9 and adding two times the door width, the simulator's width is roughly 14ft/4.25m. The drawing I found in the patent (Which depicts the third row of seating different than real one) shows a width to length ratio of roughly 1:1.5. Extrapolating, that would mean the length is roughly 21ft/6.4m The height is approximately 8.75 feet/2.75m from the numbers mentioned above. So the best guess I can come up with from that data is roughly 21x14x8.75ft or 6.4x4.25x2.75m.—FA Jon (talk) 20:17, 1 November 2017 (UTC)[reply]