Oran Township, Fayette County, Iowa

Coordinates: 42°41′05″N 92°01′27″W / 42.68472°N 92.02417°W / 42.68472; -92.02417
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Oran Township
Township
Location in Fayette County
Location in Fayette County
Coordinates: 42°41′05″N 92°01′27″W / 42.68472°N 92.02417°W / 42.68472; -92.02417
Country United States
State Iowa
CountyFayette
Area
 • Total36.66 sq mi (94.94 km2)
 • Land36.65 sq mi (94.91 km2)
 • Water0.01 sq mi (0.03 km2)  0.03%
Elevation
1,027 ft (313 m)
Population
 (2010)
 • Total760
 • Density21/sq mi (8.0/km2)
Time zoneUTC-6 (CST)
 • Summer (DST)UTC-5 (CDT)
ZIP codes
50629, 50662
GNIS feature ID0468467

Oran Township is one of twenty townships in Fayette County, Iowa, USA. As of the 2010 census, its population was 760.[1]

Geography[edit]

According to the United States Census Bureau, Oran Township covers an area of 36.66 square miles (94.94 square kilometers); of this, 36.65 square miles (94.91 square kilometers, 99.97 percent) is land and 0.01 square miles (0.03 square kilometers, 0.03 percent) is water.

Cities, towns, villages[edit]

Unincorporated towns[edit]

(This list is based on USGS data and may include former settlements.)

Adjacent townships[edit]

Cemeteries[edit]

The township contains these four cemeteries: Fairbank, Immaculate Conception, Oran Township and Oran Township.

Major highways[edit]

Airports and landing strips[edit]

  • Oelwein Municipal Airport

School districts[edit]

  • Oelwein Community School District
  • Wapsie Valley Community School District
  • West Central Community School District

Political districts[edit]

References[edit]

  1. ^ "Profile of General Population and Housing Characteristics: 2010 Demographic Profile Data (DP-1): Oran township, Fayette County, Iowa". United States Census Bureau. Retrieved March 5, 2012.

External links[edit]

Retrieved from "https://en.wikipedia.org/w/index.php?title=Oran_Township,_Fayette_County,_Iowa&oldid=1167453615"