Talk:Nuclear magneton

Suggested merger

The "Neutron magnetic moment" article seems to make sense. 173.175.54.131 (talk) 05:16, 7 July 2010 (UTC)

simple semi-Classical explanation ??

First, quarks have spin-angular-momentum of ${\hbar } \over {2}$; typical charge of ${e} \over {3}$; and typical mass of ${m_{\mathrm {p} }} \over {3}$. Accordingly, the expected quark magneton would be:

$\mu _{q}={{{{e} \over {3}}{{\hbar } \over {2}}} \over {2{{m_{P}} \over {3}}}}$

$={{\mu _{N}} \over {2}}$

Then, in units of $\mu _{q}$,

$\mu _{P}\approx 6$

$\mu _{N}\approx -4$

Then, assuming that

$\mu _{P}=2\mu _{up}+1\mu _{down}$

$\mu _{N}=-1\mu _{up}-2\mu _{down}$

Then, that system of equations can be quickly solved, yielding

$\mu _{up}={{8} \over {3}}$

$\mu _{down}={{2} \over {3}}$

Then, accounting for up-quarks having twice the normal quark charge; and attributing the remaining discrepancies to differences in up-quark vs. down-quark masses,

$m_{up}={{1} \over {4}}$

$m_{down}={{1} \over {2}}$

in units of $m_{P}$. Thus, a simple picture, of down-quarks having twice the mass, and (negative) half the charge, of up quarks; qualitatively accounts, for proton & neutron magnetons, as well as masses (neutrons heavier than protons).66.235.38.214 (talk) 03:42, 18 October 2012 (UTC)

As you can find in the page for Up quark and Down quark, typical quark masses are in fact around ${m_{\mathrm {p} }} \over {100}$, so this is clearly not helpful. Also, as far as I can tell this is original work and according to Wikipedia's policy should not be included on the page. Ragnarstroberg (talk) 15:28, 15 January 2013 (UTC)