Talk:Megagon

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Mega meaning a million[edit]

I'm surprised that this article got a consensus to keep. The table in the number prefix article doesn't mention mega for a million. Georgia guy (talk) 14:22, 20 February 2012 (UTC)[reply]

That's what you said when you nominated it, but the consensus was for "keep," for several reasons. Let it go. -- 202.124.72.200 (talk) 09:58, 21 February 2012 (UTC)[reply]

Google translate says million is εκατομμύριο or english spelling ekatommýrio, which looks like 100 10,000s. I've not seen what Conway would say, but I'd guess hectomyriagon? Tom Ruen (talk) 02:27, 20 February 2015 (UTC)[reply]

Here's a question for hecatommyriagon. And [1] 1000000 hecatommyriagon or hekatommyriagon.

Anyway, no suggestion for a name change. I'm only considering if any greek based name could at least be mentioned? Tom Ruen (talk) 02:27, 20 February 2015 (UTC)[reply]

I would actually expect hecatontakismyriagon from Ancient Greek ἑκατοντάκις μύριοι (-ριαι, -ρια), attested in Archimedes. It literally also means a hundred myriad. So immediately a few others follow: {105} decakismyriagon, {107} chiliakismyriagon, and {108} myriakismyriagon. But I doubt you'll find any of these names being used anywhere. Double sharp (talk) 03:24, 20 February 2015 (UTC)[reply]

Megagon picture[edit]

We should really have a picture of an actual regular megagon. I'm aware that this is really indistiguishable from a circle, but showing a circle instead and comparing a megagon to a circle in the caption just feels wrong. I'd make a picture myself, but the Tyler applet simply refuses to handle this polygon... Double sharp (talk) 11:38, 10 March 2013 (UTC)[reply]

If we don't need a regular one, perhaps a million sided pseudo-fractal polygon will do, like this sequence? Hilbert curve or [2] How to draw squiggles like a Hilbert Tom Ruen (talk) 02:15, 20 February 2015 (UTC)[reply]

Not that OR is recommended, but I'd support a multi-radius polygon which expresses the prime factorization 1000000 = 2^6 × 5^6, for visual clarity. So really we only need 64 radial rings of 15635 azimuthal sides. But maybe we can squish in 125 local squiggles within each ring for 125 sides? Tom Ruen (talk) 02:44, 20 February 2015 (UTC)[reply]
p.s. I am remembering the SVG renderer seeming to break down when ASCII file sizes exceed maybe 8MB, and I don't think you can draw a million points with less than 8 bytes per point, like you could express x,y="123,567", but it still would probably end up too big. Yes so on a square grid, a 1000x1000 integer grid Hilbert curve might barely survive the renderer limit. Tom Ruen (talk) 02:49, 20 February 2015 (UTC)[reply]
Here's a quick test of a fake Hilbert curve, approximately 640,000 sides, near the bitmap limit of MSPaint, although crudely scaled so not actually best using the resolution at a pixel level. Tom Ruen (talk) 03:07, 20 February 2015 (UTC)[reply]
Here's a second fake hilbert curve for 1 million edges, pixel-level scaled, red 3x3 vertices, and black edges 1 pixel thick. IE11 won't display original resolution (9400x7100 pixels), but FireFox will. Tom Ruen (talk) 03:46, 20 February 2015 (UTC)[reply]

I agree that there has to be an actual megagon picture! — Preceding unsigned comment added by 94.59.213.108 (talk) 11:55, 20 March 2015 (UTC)[reply]

Nobody's had anything to say about this in many years, but I also think someone should make an SVG with a million vertices (I would do it, but I don't know how to use Inkscape that well). jp×g 06:37, 5 May 2021 (UTC)[reply]

Slight error in edge lenth[edit]

Just looked up this page, and later found out that with parts per million, the size means that 1 part per million means 0.0001%, so with 4 parts per million = 0.0004%.

A megagon has 1 million sides, and with that, if it were drawn to the size of Earth, which is actually 12756.274 km in diameter, each edge length would actually be 51.025096 meters long(so about 50 meters, edge lengths that are 0.0004% of Earth's diameter = 51.025096), the 40 meter edge length applies for a megagon that's 10000 km in diameter.

So the article had to be edited for correction. — Preceding unsigned comment added by 68.84.249.199 (talk) 04:21, 6 May 2016 (UTC)[reply]

Do not know where 4 parts per million comes from. With the diameter you give above, the circumference at the equator is about 40074 km and a millionth part of that is about 40 m, as the article stated. If you are using information not in the article for your computation please find a reference for it. Bill Cherowitzo (talk) 05:01, 6 May 2016 (UTC)[reply]

1/1000000 of 40075 km = 40 m?[edit]

So I got notified, but when I calculated it, I realized that 1 millionth of 40075 km is actually 40.075 m, that's 40 m 2" 24 mm 199 μm 352 nm, so, over 40 m long rather than "about" 40 long. — Preceding unsigned comment added by 68.84.249.199 (talk) 05:14, 6 May 2016 (UTC)[reply]