1970 Pepsi-Cola Masters – Doubles

From Wikipedia, the free encyclopedia
Doubles
1970 Pepsi-Cola Masters
Final
ChampionsUnited States Arthur Ashe
United States Stan Smith
Runners-upCzechoslovakia Jan Kodeš
Australia Rod Laver
Score6–3, 6–4
Events
Singles Doubles
Pepsi-Cola Masters · 1975 →

Arthur Ashe and Stan Smith won the inaugural doubles tennis title at the Masters Grand Prix by defeating both teams they faced in the round-robin stage.[1]

Round robin[edit]

Key[edit]

United States Ashe
United States Smith
Czechoslovakia Kodeš
Australia Laver
Socialist Federal Republic of Yugoslavia Franulović
Australia Rosewall
United States Arthur Ashe
United States Stan Smith
6–3, 6–4 6–5, 6–5
Czechoslovakia Jan Kodeš
Australia Rod Laver
3–6, 4–6 3–6, 6–5, 6–4
Socialist Federal Republic of Yugoslavia Željko Franulović
Australia Ken Rosewall
5–6, 5–6 6–3, 5–6, 4–6

Standings[edit]

Players RR W-L Sets W-L Games W-L Standings
United States Arthur Ashe
United States Stan Smith
2–0
4–0
24–17
1
Czechoslovakia Jan Kodeš
Australia Rod Laver
1–1
2–5
22–27
2
Socialist Federal Republic of Yugoslavia Željko Franulović
Australia Ken Rosewall
0–2
1–4
25–27
3

Standings are determined by: 1. number of wins; 2. number of matches; 3. in two-players-ties, head-to-head records; 4. in three-players-ties, percentage of sets won, or of games won; 5. steering-committee decision.

References[edit]

  1. ^ "Doubles Results | Nitto ATP Finals | Tennis". Nitto ATP Finals. Retrieved 2021-11-14.