Isogonal conjugate

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  Lines from each vertex to P
  Lines to P reflected about the angle bisectors (concur at P*, the isogonal conjugate of P)
Isogonal conjugate transformation over the points inside the triangle.

In geometry, the isogonal conjugate of a point P with respect to a triangle ABC is constructed by reflecting the lines PA, PB, PC about the angle bisectors of A, B, C respectively. These three reflected lines concur at the isogonal conjugate of P. (This definition applies only to points not on a sideline of triangle ABC.) This is a direct result of the trigonometric form of Ceva's theorem.

The isogonal conjugate of a point P is sometimes denoted by P*. The isogonal conjugate of P* is P.

The isogonal conjugate of the incentre I is itself. The isogonal conjugate of the orthocentre H is the circumcentre O. The isogonal conjugate of the centroid G is (by definition) the symmedian point K. The isogonal conjugates of the Fermat points are the isodynamic points and vice versa. The Brocard points are isogonal conjugates of each other.

In trilinear coordinates, if is a point not on a sideline of triangle ABC, then its isogonal conjugate is For this reason, the isogonal conjugate of X is sometimes denoted by X –1. The set S of triangle centers under the trilinear product, defined by

is a commutative group, and the inverse of each X in S is X –1.

As isogonal conjugation is a function, it makes sense to speak of the isogonal conjugate of sets of points, such as lines and circles. For example, the isogonal conjugate of a line is a circumconic; specifically, an ellipse, parabola, or hyperbola according as the line intersects the circumcircle in 0, 1, or 2 points. The isogonal conjugate of the circumcircle is the line at infinity. Several well-known cubics (e.g., Thompson cubic, Darboux cubic, Neuberg cubic) are self-isogonal-conjugate, in the sense that if X is on the cubic, then X –1 is also on the cubic.

Another construction for the isogonal conjugate of a point[edit]

A second definition of isogonal conjugate

For a given point P in the plane of triangle ABC, let the reflections of P in the sidelines BC, CA, AB be Pa, Pb, Pc. Then the center of the circle PaPbPc is the isogonal conjugate of P.[1]

See also[edit]

References[edit]

  1. ^ Steve Phelps. "Constructing Isogonal Conjugates". GeoGebra. GeoGebra Team. Retrieved 17 January 2022.

External links[edit]